Reverse*a*Sentence*With*Ruby code

For example , if you want "One, Two, Three, Four." to be converted into “.Four ,Three ,Two ,One”, take a look at my ruby version for your reference, hope it helps in some degree :) I know you may never need this function, but some people may let you write such kind of things...

 # Ruby Version 1.9.2-p180  
 def reverseTest(inputtext)  
  @a=""  
  regextext = /[!,.;"()<>\[\]{}]/  
  arr = inputtext.split(/\s/)  
  arr.reverse_each { |item|  
   len = @a.length  
   # Dealing with a word surrounding by one or multiple punctuation  
   if item.partition(regextext).at(1)!=''  
    # Partition the word by particular punctuation, until partition by the last punctuation  
    begin  
     @a .insert(len,item.partition(regextext).at(0))  
     @a .insert(len,item.partition(regextext).at(1))  
     item = item.partition(regextext).at(2)  
    end while item.partition(regextext).at(1)!='' && item.partition(regextext).at(2)!=''  
    # When punctuation is at the end coming after a word  
    @a .insert(len,item.partition(regextext).at(0))  
    @a .insert(len,item.partition(regextext).at(1))  
    @a << ' '  
   # Dealing with a word without surrounding any punctuation  
   else  
    @a << item  
    @a << ' '  
   end  
  }  
  #Remove space at the end of the string and swap symmetry punctuation  
  @a.strip!  
  @a.gsub!(/[()<>\[\]{}]/, '('=>')', ')'=>'(', '<'=>'>', '>'=>'<', '['=>']',']'=>'[', '{'=>'}', '}'=>'{')  
  print @a  
 end